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Chemistry
An element X (atomic weight =80 g / mol ) having fcc structure, calculate the number of unit cells in 8 g of X :
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Q. An element $X$ (atomic weight $=80\, g\, / mol$ ) having fcc structure, calculate the number of unit cells in $8\, g$ of $X$ :
The Solid State
A
$0.4 \times N_{ A }$
B
$0.1 \times N_{ A }$
C
$4 \times N_{ A }$
D
$N_{ A } / 40$
Solution:
Effective number of atom in a unit cell $=4$
Number of atom $=\frac{8}{80} \times N_{ A }$
$\therefore $ Number of unit cell $=\frac{N_{ A }}{10} \times \frac{1}{4}=\frac{N_{ A }}{40}.$