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Q. An element with atomic number 84 and mass number 218 loses one a-particle and two $ \beta - $ particles in three successive stages. The resulting element will have

MGIMS WardhaMGIMS Wardha 2010

Solution:

Let element is 'A'. $ _{84}{{A}^{218}}{{\xrightarrow{\alpha -particle}}_{82}}{{B}^{214}}{{\xrightarrow{-\beta }}_{83}}{{C}^{214}} $ $ {{\xrightarrow{-\beta }}_{84}}{{D}^{214}} $ Hence, the resulting element will have at. no. 84 and mass no. 214.