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Q. An element occuring in the bcc structure has $12.08 \times 10^{23}$ unit cells. The total number of atoms of the element in these cells will be

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Solution:

There are two atoms in a bcc unit cell.
So, number of atoms in $12.08 \times 10^{23}$ unit cells
$= 2 \times 12.08 \times 10^{23} = 24.16 \times 10^{23}$ atoms.