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Q. An element is found in nature in two isotopic forms with mass numbers (A-1) and (A + 3). If the average atomic mass of the element is found to be $A$, then the relative abundance of the heavier isotope in the nature will be.

Some Basic Concepts of Chemistry

Solution:

Let relative abundance of heavier isotope be $x \%$

$A=\frac{(100-x)(A-1)+x(A+3)}{100}$

$100 A =100 A - xA -100+ x +3 x + xA$

$4 x=100$

$\therefore x=25$