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  4. An element have atomic weight 40 and its electronic configuration is 1 s2 2 s2 2 p6 3 s2 3 p6. Then its atomic number and number of neutrons will be:

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Q. An element have atomic weight $40$ and its electronic configuration is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6}$. Then its atomic number and number of neutrons will be:

Rajasthan PMTRajasthan PMT 2002Structure of Atom

Solution:

Given, electronic configuration $=1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6}$
and atomic weight $=40$
Hence, atomic number $=2+2+6+2+6$
$=18$
Number of neutrons
$=$ atomic weight $-$ atomic number
$=40-18=22$