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Chemistry
An element has [ Ar ] 3 d1 configuration in its +2 oxidation state. Its position in the periodic table is
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Q. An element has $[ Ar ] 3 d^{1}$ configuration in its $+2$ oxidation state. Its position in the periodic table is
AP EAMCET
AP EAMCET 2016
A
period-3, group-3
B
period-3, group-7
C
period-4, group-3
D
period-3, group-9
Solution:
Electronic configuration of the element in $+2$ oxidation state is [Ar] $3 d^{1}$.
This electronic configuration is obtained after losing 2 electrons.
$\therefore $ Atomic number of the element
$=$ Atomic number of $Ar +1+2$
$=18+1+2$
$=21$
Thus, element is scandium. It is a d-block element.
The electronic configuration of
$ Sc =[ Ar ] 3 d^{1} 4 s ^{2}$
Here, $n=4$ therefore, it belongs to the $4 \text{th}$ period.
Group $=$ Total number of valence shell electrons $=3$
So, the element belongs to period-$4$, group-$3$.