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Chemistry
An element has a face-centred cubic (fcc ) structure with a cell edge of a. The distance between the centres of two nearest tetrahedral voids in the lattice is :
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Q. An element has a face-centred cubic (fcc ) structure with a cell edge of a. The distance between the centres of two nearest tetrahedral voids in the lattice is :
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The Solid State
A
$\frac{a}{2}$
64%
B
a
8%
C
$\frac{3}{2} a $
12%
D
$\sqrt{2} a $
16%
Solution:
Distance between two nearest tetrahedral void $ = \left( \frac{a}{2} \right)$