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Chemistry
An element has a body centered cubic (bcc) structure with a cell edge of 288 pm. The atomic radiusis:
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Q. An element has a body centered cubic (bcc) structure with a cell edge of 288 pm. The atomic radiusis:
NEET
NEET 2020
The Solid State
A
$\frac{\sqrt{3}}{4}\times 288 \,pm$
71%
B
$\frac{\sqrt{2}}{4}\times 288 \,pm$
9%
C
$\frac{4}{\sqrt{3}}\times 288 \,pm$
15%
D
$\frac{4}{\sqrt{2}}\times 288 \,pm$
5%
Solution:
In bcc unit cell, atoms lying along a body diagonal touch each other
Length of body diagonal $=\sqrt{3}a$
$\sqrt{3}a=4r$
$r=\frac{\sqrt{3}}{4}a$
As $a=288\,pm$
$\therefore r=\frac{\sqrt{3}}{4}\times288Pm$
