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Q. An element (atomic mass $100 \,g /\, mol$ ) having $BCC$ structure has unit cell edge $400\, pm$. The density of element is (No. of atom in $BCC ( Z )=2$ ).

AIPMTAIPMT 1996The Solid State

Solution:

No. of atoms per unit cell in $b.c.c.$ lattice $(n) = 2$

Density, $d = \frac{n \times M}{a^3 \times N_A}$

$ = \frac{2\times 100}{(4\times 10^{-8}\,cm)^3 \times 6.02 \times 10^{23}}$

$ = \frac{200}{38.528} $

$ = 5.19\,g/cm^3$.