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Q. An electron of mass M kg and charge coulomb travels from rest through a potential difference of V volt. The final, y velocity of the electron is (in m7s)

Electrostatic Potential and Capacitance

Solution:

Energy gained by an electron
$= q \Delta V$ $= V \times e$
this energy is in the from kinetic energy
$\Rightarrow \frac{1}{2} Mv _{ f }^{2}= V \times e$
$\Rightarrow v _{ f }^{2}=\frac{2 eV }{ M }$
$\Rightarrow v _{ f }=\sqrt{\frac{ 2 e V }{ M }}$