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  4. An electron of mass m and charge e is accelerated from rest through a potential difference V in vacuum. The final speed will be

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Q. An electron of mass m and charge e is accelerated from rest through a potential difference V in vacuum. The final speed will be

MGIMS WardhaMGIMS Wardha 2007

Solution:

Kinetic energy of electron = eV $ \Rightarrow $ $ \frac{1}{2}m{{v}^{2}}=eV $ $ \Rightarrow $ $ v=\sqrt{\frac{2eV}{m}} $