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Q. An electron moving with a constant velocity $v$ along $X-$axis enters a uniform electric field applied along $Y-$axis. Then the electron moves

KEAMKEAM 2015Electric Charges and Fields

Solution:

At the position $X$, we have
image
Time taken by an electron $t=\frac{X}{V}$ ...(i)
and displacement of an electron
$y=\frac{1}{2} a t^{2}=\frac{1}{2} \frac{E_{e}}{m} t^{2}$
From Eq. (i), $y=\frac{1}{2} \frac{E_{e}}{m} \frac{x^{2}}{v^{2}}$
$\Rightarrow y=a x^{2}$
[$\therefore $ acceleration, $a=\frac{E_{e}}{2 m v^{2}}$]
So, the trajectory represented as
$y=a x^{2}$ (Parabola)