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Q. An electron (mass = $9.1 \, \times \, 10^{- 31 \, }kg$ ; charge = $- \, 1.6 \, \times \, 10^{- 19} \, C$ ) experiences no deflection if subjected to an electric field of $3.2 \, \times \, 10^{5} \, V \, m^{- 1}$ and a magnetic field of $2.0 \, \times \, 10^{- 3} \, \, Wb \, m^{- 2}$ . Both the fields are normal to the path of electron and to each other. If the electric field is removed, then the electron will revolve in an orbit radius

NTA AbhyasNTA Abhyas 2020Moving Charges and Magnetism

Solution:

$\overset{ \rightarrow }{F}_{\text{e}}+\overset{ \rightarrow }{F}_{\text{m}}=0\Rightarrow F_{\text{e}}=F_{\text{m}}\Rightarrow \textit{eE}=\textit{eVB}$
$v=\frac{E}{B}\Rightarrow \frac{\text{3.2} \times 1 0^{5}}{2 \times 1 0^{- 3}}=\text{1.6}\times 10^{8}ms^{- 1}$
$r=\frac{m v}{q B}=\frac{\text{9.1} \times 1 0^{- 3} \times \text{1.6} \times 1 0^{8}}{\text{1.6} \times 1 0^{- 1 9} \times 2 \times 1 0^{- 3}}=\text{0.45 m}$