1. Tardigrade
  2. Question
  3. Physics
  4. An electron makes transition from n=3 to the orbit n=2 of a hydrogen atom (ionization potential 13.6 eV ). The energy of the photon emitted in the process is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. An electron makes transition from $ n=3 $ to the orbit $ n=2 $ of a hydrogen atom (ionization potential $13.6\, eV$ ). The energy of the photon emitted in the process is

BHUBHU 2010

Solution:

Energy released
$=13.6\left[ \frac{1}{{{(1)}^{2}}}-\frac{1}{{{(3)}^{2}}} \right] $
$=12.09\text{ }eV $