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  4. An electron is accelerated through a potential difference of 1000 volt. The velocity acquired by the electron is

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Q. An electron is accelerated through a potential difference of 1000 volt. The velocity acquired by the electron is

Dual Nature of Radiation and Matter

Solution:

K.E. acquired by electron. $\frac{1}{2}mv^2$ = eV or $v =\sqrt{\frac{2eV}{m}}$ i.e. $v = \sqrt{\frac{2 \times 1.6 \times 10^{-19} \times 1000}{9.1 \times 10^{-31}}}$ = 1.88 $\times 10^7 \, m \, s^{-1}$