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Q. An electron is accelerated through a potential difference of 10,000 V. Its de Broglie wavelength is. (nearly): (mt. = $9 \times 10^{-31}$ kg)

NEETNEET 2019Dual Nature of Radiation and Matter

Solution:

For an electron accelerated through a potential V $\lambda = \frac{12.27}{\sqrt{V} } \mathring A = \frac{12.27 \times10^{-10}}{\sqrt{10000}} = 12.27 \times10^{-12} m $