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Physics
An electron is accelerated through a potential difference of 10,000 V. Its de Broglie wavelength is. (nearly): (mt. = 9 × 10-31 kg)
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Q. An electron is accelerated through a potential difference of 10,000 V. Its de Broglie wavelength is. (nearly): (mt. = $9 \times 10^{-31}$ kg)
NEET
NEET 2019
Dual Nature of Radiation and Matter
A
$12.2\times 10^{11}$m
8%
B
12.2 nm
14%
C
$12.2\times 10^{13}$m
17%
D
$12.2\times 10^{-12}$m
61%
Solution:
For an electron accelerated through a potential V $\lambda = \frac{12.27}{\sqrt{V} } \mathring A = \frac{12.27 \times10^{-10}}{\sqrt{10000}} = 12.27 \times10^{-12} m $