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Q.
An electron is accelerated through a potential difference of 1000 V. Its velocity is nearly
Rajasthan PMTRajasthan PMT 2010
Solution:
If the voltage given is $ V $ , then the energy of electron $ =\frac{1}{2}m{{v}^{2}}=eV $ $ v=\sqrt{\frac{2eV}{m}} $ $ =\sqrt{\frac{2\times 1.6\times {{10}^{-19}}\times 1000}{9.1\times {{10}^{-31}}}} $ $ =1.875\times {{10}^{7}} $ $ =1.9\times {{10}^{7}}\,\,m/s $