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Q. An electron having mass m and kinetic energy $E$ enter in uniform magnetic field $B$ perpendicularly, then its frequency will be

AIPMTAIPMT 2001Moving Charges and Magnetism

Solution:

The frequency of revolution of charged particle in a perpendicular magnetic field is
$\upsilon = \frac{1}{T} = \frac{ 1}{ 2 \pi r /v }$
$ = \frac{ v}{ 2\pi r} = \frac{v}{2 \pi } \times \frac{ e B }{mv }$
$ = \frac{eB}{2 \pi m }$.