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Chemistry
An electron has principal quantum number 3. The number of its (i) sub-shells and (ii) orbitals would be respectively
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Q. An electron has principal quantum number $3$. The number of its (i) sub-shells and (ii) orbitals would be respectively
Structure of Atom
A
$3$ and $5$
17%
B
$3$ and $7$
8%
C
$3$ and $9$
60%
D
$2$ and $5$
15%
Solution:
The principal quantum number $n = 3.$ Then azimuthal quantum number $l=3$ and number of orbitals $= n^{2} = 3^{2} =$ $9.3$ and $9$.