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  4. An electron falls through a distance h in a uniform electric field E, the direction of E is reversed and a proton falls through the same distance. The ratio of the time of fall of electrons to that of the proton is

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Q. An electron falls through a distance $h$ in a uniform electric field $E,$ the direction of $E$ is reversed and a proton falls through the same distance. The ratio of the time of fall of electrons to that of the proton is

Electric Charges and Fields

Solution:

$a=\frac{e E}{m} ; h=\frac{1}{2} a t^{2}$ or $t=\sqrt{\frac{2 h}{a}} \Rightarrow t=\sqrt{\frac{2 h \cdot m}{e E}}$
Thus, $\frac{t_{e}}{t_{P}}=\sqrt{\frac{m_{e}}{m_{P}}}$.