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Q. An electron enters uniform electric field maintained by parallel plates and of value $ EV{{m}^{-1}} $ with a velocity $ v\text{ }m{{s}^{-1}}, $ the plates are separated by a distance $ d $ metre, then acceleration of the electron in the field is:

KEAMKEAM 2004

Solution:

$ F=eE $
Therefore, acceleration in electron due to force F
$ a=\frac{F}{m}=\frac{eE}{m} $