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Q. An electron enters between two horizontal plates separated by $2\, mm$ and having a potential difference of $1000\, V$. The force on electron is

Electrostatic Potential and Capacitance

Solution:

Force on electron, $F=Q E=Q\left(\frac{V}{d}\right)$
$\Rightarrow F=\left(1.6 \times 10^{-19}\right)\left(\frac{1000}{2 \times 10^{-3}}\right)$
$=8 \times 10^{-14} N$