Question

An electron (charge $=1.6 \times 10^{-19}$ coulomb) is moving in a circle of radius $5.1 \times 10^{-11} m$ at a frequency of $6.8 \times 10^{15}$ revolution/sec. The equivalent current is approximately

• A. $5.1 \times 10^{-3} A$
• B. $6.8 \times 10^{-3}$ A
• C. $1.1 \times 10^{-2} A$
• D. $2.2 \times 10^{-2} A$

Answer 1

Answer: (C)

As we know:
$I=q v$
$ \Rightarrow 1.6 \times 10^{-19} \times 6.8 \times 10^{16}=11 \times 10^{-3} A$
$I=1.1 \times 10^{-2} A$