Q.
An electron beam can undergo diffraction by crystals. The potential of 'V' volt should a beam of electrons be accelerated so that its wavelength becomes equal to $1.0 \, \mathring{A} $ . The value of 'V' is
Given: $\frac{h^{2}}{m_{e} \times e} = 3 \times 10^{- 18} J^{2} s^{2} kg^{- 1} coulomb^{- 1}$
NTA AbhyasNTA Abhyas 2020Structure of Atom
Solution: