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Q. An electrolytic cell is composed of $Cu$ and $Zn$. A current of $9.65 \,A$ is drawn from a cell for $1$ hour. Then the loss in mass at anode and gain in mass at cathode, respectively could be

Electrochemistry

Solution:

For $Cu$ (at cathode)
$W =\frac{ E }{96500} \times it =\frac{\frac{63.5}{2}}{96500} \times 9.65 \times 1 \times 60 \times 60=11.43\, g$
$E=\frac{\text { molar mass }}{n-\text { factor }}=\frac{63.5}{2 \leftarrow\left(C u^{+2}\right)}$