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  4. An electric lift with a maximum load of 2000 kg (lift+ passengers) is moving up with a constant speed of 1.5 ms -1. The frictional force opposing the motion is 3000 N. The minimum power delivered by the motor to the lift in watts is: (g=10 ms -2)

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Q. An electric lift with a maximum load of $2000\, kg$ (lift+ passengers) is moving up with a constant speed of $1.5 \,ms ^{-1}$. The frictional force opposing the motion is $3000\, N$. The minimum power delivered by the motor to the lift in watts is : $\left(g=10 \,ms ^{-2}\right)$

NEETNEET 2022Work, Energy and Power

Solution:

Constant velocity $\Rightarrow a =0$
$\Rightarrow T = W + f $
$=20000+3000$
$=23000 \,N$
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$ \Rightarrow $ Power $= Tv $
$=23000 \times 1.5 $
$=34500 $ watts