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  4. An electric lamp is connected to 220 V , 50 Hz supply. Then the peak value of voltage is

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Q. An electric lamp is connected to $220 \,V , 50\, Hz$ supply. Then the peak value of voltage is

Alternating Current

Solution:

$V_{0}=V_{ rms } \times \sqrt{2}=220 \times \sqrt{2}=310 \,V$