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  4. An electric immersion heater of 1.08 kW is immersed in water. After the water has reached a temperature of 100° C, how much time will be required to produce 100 g of steam?

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Q. An electric immersion heater of $1.08 \,kW$ is immersed in water. After the water has reached a temperature of $ 100^{\circ }\,C, $ how much time will be required to produce $100\, g $ of steam?

BHUBHU 2010Electromagnetic Induction

Solution:

$L$ is the latent heat of vaporization of water; the heat required for producing $1 \,g$ of steam,
$L=540\, cal =540 \times 4.2=2268\, J$
Energy supplied
$=1080\, J / s$
Time required to boil $100 \,g$ of water
$=540 \times 4.2 \times 100 / 1080 $
$=210\, s$