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  4. An electric immersion heater of 1.08 kW is immersed in water. After the water has reached a temperature of 100?C, how much time will be required to produce 100 g of steam?

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Q. An electric immersion heater of 1.08 kW is immersed in water. After the water has reached a temperature of 100?C, how much time will be required to produce 100 g of steam?

BVP MedicalBVP Medical 2005

Solution:

The heat required for producing 1 g of steam $ =540cal=540\times 4.2J=2268J $ Energy given by immersion heater is $ =1.08\,kW=1080W $ Now time taken in boiling 100 g of water $ =\frac{2268\times 100}{1080}=210\sec $