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Q. An electric dipole of moment $p$ is placed in an electric field of intensity $E$. The dipole acquires a position such that the axis of the dipole makes an angle $\theta$ with the direction of the field. Assuming that the potential energy of the dipole to be zero when $\theta= 90^{\circ}$, the torque and the potential energy of the dipole will respectively be

AIPMTAIPMT 2012Electric Charges and Fields

Solution:

Potential energy of the dipole
$U =-\int T dB =-\int\limits_{\pi / 2}^{\theta} PE \sin \theta d \theta$
$= PE (\cos \theta-0)=- PE \cos \theta$
and potential energy $= PE \sin \theta$.