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Q. An electric dipole has the magnitude of its charge as $q$ and its dipole moment is $p$. It is placed in a uniform electric field $E$. If its dipole moment is along the direction of the field, the force on it and its potential energy are respectively

ManipalManipal 2007Electrostatic Potential and Capacitance

Solution:

An electric dipole is an arrangement of two equal an opposite charges placed at a distance $2 l$ The dipole is placed in electric field as such its dipole moment is in direction of electric field as shown in figure
image
Now force on the charge $q$ is $F_{2}=q E$ along the direction of $E$ and force on charge $-q$ is $F_{1}=-q E$ in the direction opposite to $E$.
Since, forces on the dipole are equal and opposite, so net force on the electric dipole is zero.
image
Now potential energy of the dipole.
$U=-p E \cos \theta$
where $\theta$ is the angle between direction of electric field and direction of dipole moment.
$\therefore \theta=0^{\circ}$
Hence, $U=-p E \cos 0^{\circ}=-p E$ (minimum)