1. Tardigrade
  2. Question
  3. Chemistry
  4. An electric current of 0.965 ampere is passed for 2000 s through a solution containing [Cu(CH3CN)4]+ and metallic copper is deposits d at the cathode. The amount of Cu deposited is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. An electric current of 0.965 ampere is passed for 2000 s through a solution containing $ {{[Cu{{(C{{H}_{3}}CN)}_{4}}]}^{+}} $ and metallic copper is deposits d at the cathode. The amount of Cu deposited is

VMMC MedicalVMMC Medical 2015

Solution:

$ {{[Cu{{(C{{H}_{3}}CN)}_{4}}]}^{+}}+{{e}^{-}}\xrightarrow[{}]{{}}Cu+4C{{H}_{3}}CN $ For the above reaction 1 F charge is required to deposit 1 mole of Cu (i.e. 63.5 g) Charge supplied $ =0.965\times 2000 $ $ =2\times 965=0.02\text{ }F $ $ \therefore $ Moles of Cu deposited = 0.02 mol