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Q. An electric bulb marked as $50 W-200\, V$ is connected across a $100\, V$ supply. The power consumed by the bulb at present is

JIPMERJIPMER 2013Current Electricity

Solution:

We know that $R=\frac{V^{2}}{P}$
Given $V=200\, V ,\, P=40\, W$
and $V'=100\, V$
Hence, $R=\frac{V^{2}}{P}=\frac{200 \times 200}{50}$
$P'=\frac{V^{2}}{R}=\frac{100 \times 100 \times 50}{200 \times 200}$
$P'=12.5\, W$