1. Tardigrade
  2. Question
  3. Chemistry
  4. An atomic solid crystallizes in a body centre cubic lattice and the inner surface of the atoms at the adjacent corner are separated by 60.3 pm. If the atomic weight of A is 48 , then density of the solid, is nearly:

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Q. An atomic solid crystallizes in a body centre cubic lattice and the inner surface of the atoms at the adjacent corner are separated by $60.3\, pm$. If the atomic weight of $A$ is 48 , then density of the solid, is nearly:

The Solid State

Solution:

Given $a-2 r=60.3$ and for bcc, $4 r=\sqrt{3}$

$\Rightarrow a -\frac{\sqrt{3}}{2} a =60.3$

$\Rightarrow a =450\, pm$

Density $(\rho)=\frac{2 \times 48}{6.023 \times 10^{23} \times(4.5)^{3} \times 10^{-24}}$

$=1.75\, g / cc$