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Q. An artillery piece which consistently shoots its shells with the same muzzle speed has a maximum range $R$ . To hit a target which is $\frac{R}{2}$ from the gun and on the same level, the angle of elevation of the gun should be

NTA AbhyasNTA Abhyas 2020Motion in a Plane

Solution:

$R_{\text{max}}=R=\frac{u^{2}}{g}$ (at an angle of $45^\circ $ )
$u^{2}=Rg$
Using $\text{Range}=\frac{u^{2} \text{sin} 2 \theta }{g}$
then $\frac{R}{2}=\left(\textit{Rg}\right)\frac{\text{sin} 2 \theta }{g}$
$\text{sin} 2 \theta = \frac{1}{2}$
$2\theta =30^\circ \Rightarrow \theta =15^\circ $