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Q.
An artificial satellite moves in a circular orbit around the earth. Total energy of the satellite is $E$. then what is the potential energy of satellite
Gravitation
Solution:
$U =\frac{- GM _{ e } m }{ R _{ e }}$
$KE =\frac{1}{2} \frac{ GM _{ e }}{ R _{ e }}$
$TE = U + K =\frac{-1}{2} \frac{ GM _{ e } m }{ R _{ e }}$
$U =-2 E$