Question

An arc of radius $R$ is shown in the figure, find the potential at its centre:-

• A. $\frac{6 k Q}{R}$
• B. $\frac{5 k Q}{R}$
• C. $\frac{\sqrt{3} k Q}{R}$
• D. $\frac{\sqrt{2} k Q}{R}$

Answer 1

Answer: (A)

$V=\frac{k \left(\right. 6 Q \left.\right)}{R}=\frac{6 k Q}{R}$
(potential is scalar)