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Q. An aqueous solution of glucose is $ 20\% $ in strength. The volume in which $ 1\, g $ - mole of it is dissolved will be :

UPSEEUPSEE 2006

Solution:

$\because 20\,g$ glucose is dissolved in $100\,mL$ solution
$ ∴ 1\,g$ glucose is dissolved in $= \frac{100}{20}$
$180\,g $( $g$-mole) glucose is dissolved in
$ = \frac {100 × 180}{20} = 900\, mL = 0 .9\, L$