1. Tardigrade
  2. Question
  3. Chemistry
  4. An aqueous solution containing ionic salt having molality equal to 0.1892 freezes at -0.704° C. The van't Hoff factor of the ionic salt will be equal to ( K f =1.86 Km -1)

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Q. An aqueous solution containing ionic salt having molality equal to $0.1892$ freezes at $-0.704^{\circ} C$. The van't Hoff factor of the ionic salt will be equal to _____ $\left( K _{ f }=1.86\, Km ^{-1}\right)$

Solutions

Solution:

$\Delta T _{ f }= i \times K _{ f } \times m$
$0-(-0.704)= i \times 1.86 \times 0.1892$
$i =\frac{0.704}{1.86 \times 0.1892} \approx 2$