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Q. An aqueous solution containing $6.5 \, gm$ of $NaCl$ of $90\%$ purity was subjected to electrolysis. After the complete electrolysis, the solution was evaporated to get solid $NaOH$. The volume of $1\, M$ acetic acid required to neutralise $NaOH$ obtained above is

KCETKCET 2009Some Basic Concepts of Chemistry

Solution:

Weight of pure $NaCl =6.5 \times 0.9=5.85 \,g$

No. of equivalence of $NaCl =\frac{5.85}{58.5}=0.1$

No. of equivalence of $NaOH$ obtained $=0.1$

Volume of $1 \,M$ acetic acid required for the

neutralisation of $ NaOH =\frac{0.1 \times 1000}{1} $

$=100 \,cm ^{3}$