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Q. An amplitude modulated wave is represented by the expression $v _{ m }=5(1+0.6 \cos 6280 t )$ $\sin \left(211 \times 10^{4} t \right)$ volts. The minimum and maximum amplitudes of the amplitude modulated wave are, respectively :

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Solution:

$V _{ m }=5(1+0.6 \cos 6280 t ) \sin \left(211 \times 10^{4} t \right)$
$V _{ m }=[5+3 \cos 6820 t ] \sin \left(211 \times 10^{4} t \right)$
$V _{\max }=5+3=8$
$V _{\text {min. }}=5-3=2$