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Physics
An ammeter reads upto 1 ampere. Its internal resistance is 0.81 ohm. To increase the range to 10 A the value of the required shunt is
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Q. An ammeter reads upto $1$ ampere. Its internal resistance is $0.81\, ohm$. To increase the range to $10\, A$ the value of the required shunt is
AIEEE
AIEEE 2003
Current Electricity
A
$0.03\, Ω$
B
$0.3\, Ω$
C
$0.9\, Ω$
D
$0.09\, Ω$
Solution:
$S=\frac{I_{g}G}{I-I_{g}}=\frac{1\times0.81}{10-1}=0.09\, Ω$