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Q. An ammeter reads upto $1$ ampere. Its internal resistance is $0.81\, ohm$. To increase the range to $10\, A$ the value of the required shunt is

AIEEEAIEEE 2003Current Electricity

Solution:

$S=\frac{I_{g}G}{I-I_{g}}=\frac{1\times0.81}{10-1}=0.09\, Ω$