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Physics
An ammeter, a voltmeter V and a resistance R are connected as shown. Ammeter reads 2 A . Voltmeter reading is 10 V. Then R is
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Q. An ammeter, a voltmeter $V$ and a resistance $R$ are connected as shown. Ammeter reads $2 \, A$ . Voltmeter reading is $10 \, V$. Then $R$ is
COMEDK
COMEDK 2008
Moving Charges and Magnetism
A
$50 \, \Omega $
4%
B
$> 5 \, \Omega $
41%
C
$< 5 \, \Omega $
30%
D
dependent on resistance of voltmeter
26%
Solution:
Voltmeter reading, $V = 10 \, V$,
Ammeter reading, $I = 2 \, A$
$V=I_1R = 10$ Here, $I_1 < 2A,$
· So $R > 5 \Omega$
This happens due to resistance of voltmeter.