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Q. An alternating voltage is connected in series with a resistance $R$ and an inductance $L .$ If the potential drop across the resistance is $200 \,V$ and across the inductance is $150\, V$, then the applied voltage is

Alternating Current

Solution:

The applied voltage is given by
$V=\sqrt{V_{R}^{2}+V_{L}^{2}}$
$V=\sqrt{(200)^{2}+(150)^{2}}=250 \text { volt }$