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Physics
An alternating current of rms value 10 A is passed through a 12 Ω resistor. The maximum potential difference across the resistor is
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Q. An alternating current of $rms$ value $10 \,A$ is passed through a $12\, \Omega$ resistor. The maximum potential difference across the resistor is
Manipal
Manipal 2009
Alternating Current
A
20 V
6%
B
90 V
12%
C
169.68 V
71%
D
none of these
10%
Solution:
$I_{0} =I_{ rms } \times \sqrt{2}$
$=10 \sqrt{2} A$
$\therefore $ Maximum potential difference $=V_{0}$
$=12 \times 10 \sqrt{2}$
$=120 \times 14.14=169.68 \,V$