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  4. An α - particle with kinetic energy K is heading towards a fixed nucleus of atomic number Z. The distance of its closest approach is directly proportional to

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Q. An $\alpha -$ particle with kinetic energy $K$ is heading towards a fixed nucleus of atomic number $Z.$ The distance of its closest approach is directly proportional to

NTA AbhyasNTA Abhyas 2020

Solution:

$K=\frac{\left(\right. Z e \left.\right) \left(\right. Z e \left.\right)}{4 \pi ϵ_{0} r}$
$r \propto \frac{Z}{K}$