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Chemistry
An alkene CH3CH = CH2 is treated with B2H6 in presence of H2O2. The final product formed is
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Q. An alkene $CH_3CH = CH_2$ is treated with $B_2H_6$ in presence of $H_2O_2$. The final product formed is
Alcohols Phenols and Ethers
A
$CH_3CH_2CHO$
B
$CH_3CH(OH)CH_3$
C
$CH_3CH_2CH_2OH$
D
$(CH_3CH_2CH_2)_3B$
Solution:
Correct answer is (c) $CH_3CH_2CH_2OH$