Question

An alcohol X on heating with concentrated $H_{2}SO_{4}$ gives an alkene Y which can show geometrical isomerism. The alcohol X is

• A. $CH_{3}CH_{2}CH\left(O H\right)CH_{3}$
• B. $\left(C H_{3}\right)_{2}C\left(O H\right)CH\left(C H_{3}\right)_{2}$
• C. $\left(C H_{3}\right)_{3}C\left(O H\right)$
• D. $\left(C H_{3}\right)_{2}C\left(O H\right)CH_{2}CH_{3}$

Answer 1

Answer: (A)

$\underset{\left(X\right)}{C H_{3} C H_{2} C H \left(O H\right) C H_{3}}\xrightarrow{conc . H_{2} S O_{4}}\underset{\left(Y\right)}{C H_{3} C H = C H C H_{3}}$