Question

An alcohol (A) on dehydration gives (B), which on Ozonolysis gives acetone and formaldehyde. (B) decolourises alkaline $KMnO_{4}$ solution but (A) does not. (A) and (B) are respectively

• A. $CH_{3}CH_{2}CH_{2}CH_{2}OH$ and $CH_{2}CH_{2}CH = CH_{2}$
• B. $CH_{3}CH_{2} - \overset{C}{\underset{O}{|}}H-CH_{3}$ and $CH_{3}-CH = CH-CH_{3}$
• C. $(CH_{3})_{3}C —OH$ and $(CH_{3})_{2}C = CH_{2}$
• D. $(CH_{3})_{3}CCH_{2}—OH$ and $(CH_{3})_{2}C=CH_{2}$

Answer 1

Answer: (C)

Correct answer is (c) $(CH_{3})_{3}C —OH$ and $(CH_{3})_{2}C = CH_{2}$