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Q. An aircraft loops a vertical loop of radius $R \, = \, 500 \, m$ with a constant velocity $v=360 \, kmh^{- 1}$ . Find the weight of the flier of mass $m=70 \, kg$ in the lower, upper, and middle points of the loop.

NTA AbhyasNTA Abhyas 2020Laws of Motion

Solution:

Forces on the flier in the frame of aircaraft (non inertial reference frame) is:
(i) Normal reaction (N)
(ii)Pseudo force $\left(\frac{m v^2}{R}\right)$
(iii) Gravitational force d(mg)
According to problem,
vT = vb = vm = v
The net force on flier at every point should be zero in the frame of aircraft. For top point T,
$N_{T} + \text{mg} = \frac{ mv _{\text{T}}^{2}}{ R ⁡} \therefore N_{T} = \frac{mv ⁡^{2}}{ R ⁡} - \text{mg}$
= 0.7 kN
For bottom point, $ N _{ B ⁡} = \text{mg} + \frac{ mv ⁡_{b}^{2}}{ R ⁡} = \text{mg} + \frac{ mv ⁡^{2}}{ R ⁡}$
= 2.1 kN.
Solution
For middle point, $N_{m} = \sqrt{\left(\frac{\text{mv}_{}^{2}}{R}\right)^{2} + \left(\text{mg}\right)^{2}} = 1 \text{.} 5 k N $